10-9v^2=-305

Solution for 10-9v^2=-305 equation:

10-9v^2=-305

We move all terms to the left:

10-9v^2-(-305)=0

We add all the numbers together, and all the variables

-9v^2+315=0

a = -9; b = 0; c = +315;
Δ = b2-4ac
Δ = 02-4·(-9)·315
Δ = 11340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11340}=\sqrt{324*35}=\sqrt{324}*\sqrt{35}=18\sqrt{35}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{35}}{2*-9}=\frac{0-18\sqrt{35}}{-18}
=-\frac{18\sqrt{35}}{-18}
=-\frac{\sqrt{35}}{-1}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{35}}{2*-9}=\frac{0+18\sqrt{35}}{-18}
=\frac{18\sqrt{35}}{-18}
=\frac{\sqrt{35}}{-1}
$